48a-28a^2+4a=0

Solution for 48a-28a^2+4a=0 equation:

48a-28a^2+4a=0

We add all the numbers together, and all the variables

-28a^2+52a=0

a = -28; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·(-28)·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*-28}=\frac{-104}{-56}
=1+6/7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*-28}=\frac{0}{-56}
=0
$